help please this is due in 20 minutes!
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Step-by-step explanation:
sum of three no =94
first no =X
second no x-8
third no =4(x-8)
X+(x-8)+4x-32=94
6x-40=94
6x=94-40
6x=54
X=54/6
X=9
Answer: The first number is 9, the second number is 17, and the third number is 68.
Step-by-step explanation:
Using the given information we will represent the first number by f , the second number by s, and the third number by t.
The first number is 8 less than the second and we will represent that by the equation, f= s-8
The third number is 4 times the second and it will be represented by the expression, t= 4s
We know the sum of the numbers has to equal 94 so we will add them.
The first number is s-8, the second is s, and the third is 4s.
(s - 8) + (s) + 4(s) = 94 Solve for s to find the second number.
6s - 8 = 94
+8 +8
6s = 102
s = 17
The second number is 17 and we will input 17 in for s to solve for the first and third numbers.
f= 17 - 8
f= 9
The first number is 11.
t= 4(17)
t = 68
The third number is 68.
Check: Now add them to see if they equal to 94.
9+ 17 + 68 = 94
94 = 94