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If the mass of Mars is 0.107 times that of Earth, and its radius is 0.530 that of Earth, estimate the gravitational acceleration g at the surface of Mars. (gearth = 9.80 m/s2

Respuesta :

To develop this problem we will use the gravitational equations posed in the Newtonian theory and for which gravity is described as,

[tex]a = \frac{GM_{mars}}{R^2_{mars}}[/tex]

Where,

G = Gravitational Universal constant

[tex]M_{mars}[/tex]= Mass of mars

[tex]R_{mars}[/tex]= Radius of mars

Using the relation given we have,

[tex]a = \frac{G*(0.107*M_e)}{(0.53R_e)^2}[/tex]

[tex]a = \frac{GM_E}{R^2_E}*\frac{0.107}{0.53^2}[/tex]

The first term is known to all as gravity on earth, which is equivalent to [tex]9.8m / s ^ 2[/tex]

[tex]a = 9.8*0.381[/tex]

[tex]a = 3.73m/s^2[/tex]

Therefore the gravitational acceleration at the surface of Mars is [tex]3.73m/s^2[/tex]

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