Answer:
The equivalent to three over five (3y + 15) is nine over five y + 9 ⇒ C
Step-by-step explanation:
Let us solve the question
∵ Three over five means [tex]\frac{3}{5}[/tex]
∴ Three over five (3y + 15) = [tex]\frac{3}{5}[/tex] (3y + 15)
→ By using the distributive property, multiply each term inside the
bracket by three over 5
∴ [tex]\frac{3}{5}[/tex] (3y + 15) = [tex]\frac{3}{5}[/tex] (3y) + [tex]\frac{3}{5}[/tex] (15)
→ Multiply three over five by 3y
∵ [tex]\frac{3}{5}[/tex] (3y) = [tex]\frac{3(3)}{5}[/tex] (y) = [tex]\frac{9}{5}[/tex] y
→ Multiply three over five by 15
∵ [tex]\frac{3}{5}[/tex] (15) = [tex]\frac{3(15)}{5}[/tex] = [tex]\frac{45}{5}[/tex] = 9
∴ [tex]\frac{3}{5}[/tex] (3y) + [tex]\frac{3}{5}[/tex] (15) = [tex]\frac{9}{5}[/tex] y + 9
∴ [tex]\frac{3}{5}[/tex] (3y + 15) = [tex]\frac{9}{5}[/tex] y + 9
∴ The equivalent to three over five (3y + 15) is [tex]\frac{9}{5}[/tex] y + 9
