Question

How much energy is required to heat 108.1g H2O (molar mass = 18.01) from a liquid at 65°C to a gas at 115°C?

Answer 1

Answer:

The energy is 22.592 kJ.

Explanation:

Given that,

Mass of $H_{2}O$ = 108.1 g

Molar mass = 18.01

Initial temperature = 65°C

Final temperature = 115°C

We need to calculate the energy

Using formula of energy

$Q_{1}=mc\Delta T$

Put the value into the formula

$Q_{1}=108.1\times4.18(115-65)$

$Q_{1}=22592.9\ J$

$Q_{1}=22.592\ kJ$

Hence, The energy is 22.592 kJ.