Answer: 0.1359
Step-by-step explanation:
This is a Poisson distribution. The formula for calculating Poisson distribution is given as :
P (X = x) = [tex]\frac{e^{-λ}λ^{x}}{x!}[/tex]
λ = 3.5
To find the probability that at most one accident occur today implies that , accident might not happen at all , the maximum accident that can happen is 1, substituting this into the formula , we have
P(X=0) = [tex]\frac{e^{-3.5}3.5^{0} }{0!}[/tex]
P(X=0) = 0.0302
P(X=1) = [tex]\frac{e^{-3.5}3.5^{1} }{1!}[/tex]
P(X=1) = 0.1057
Therefore , the probability that at most one accident occurs today.
= 0.0302 + 0.1057
= 0.1359
P(x=2) = [tex]\frac{e^{-3.5}3.5^{2} }{2!}[/tex]
P(X=2) = 0.1850
