Question

How many grams is 3.89 x 10^28 atoms of Sulfur?

Answer 1

Answer:

$M=2.06\times 10^6\ g$

Explanation:

In this problem, we need to find how many grams is 3.89 x 10²⁸ atoms of Sulfur.

It can be calculated using below formula :

$\text{No of atoms}=\dfrac{\text{Mass}}{\text{Molar Mass}}\times \text{Avagadro's number}\\\\\text{Mass}=\dfrac{\text{No. of atoms}\times \text{Molar mass}}{\text{Avagadro's number}}\\\\\text{Mass}=\dfrac{3.89\times 10^{28}\times 32}{6.022\times 10^{23}}\\\\\text{Mass}=2067087.34\ g\\\\\text{or}\\\\M=2.06\times 10^6\ g$

So, the mass of Sulfur is $2.06\times 10^6\ g$.