I apologize if this is wrong —
Square #1 and #2 has an area of 256.
Since we know the squares are identical, we can make an equation using the side lengths.
Equation —> 3x + 7 = 5x + 1
After solving for x, we see that x is equal to 3.
Now, we can subtitute the value of x into one of the side lengths. Let's substitute it into 5x + 1. After solving, we see that the final answer is 16.
Now let's do it for the other side length: 3x + 7. After solving, we see that the final answer is ALSO 16.
Now to get the area, we multiply the length and width, but since we know a square's length is width are equal, we can simply square 16. 16 multiplied by 16 is 256. Therefore, the area of square #1 is 256.
To check, we can solve for the area of square #2.
After substituting into 5x + 1, we get 16, as said earlier. When we square 16, we get 250. Therefore, the area of square #2 is 256 as well.
