Tickets to the zoo cost $12 for adults and $8 for children. The school
has a budget of $240 for the field trip. An equation representing the
budget for the trip is 240 = 12x + 8y. Here is a graph of this equation.

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Answer:

Step-by-step explanation:

Given

[tex]240 = 12x + 8y[/tex]

Required

Plot a graph

First, we need to determine the minimum and maximum values of x and y

For x:

Minimum = 0

For maximum; Let y = 0

[tex]240 = 12x + 8y[/tex]

[tex]240 = 12x + 8 * 0[/tex]

[tex]240 = 12x[/tex]

Solve for x

[tex]x = 240/12[/tex]

[tex]x = 20[/tex]

For y:

Minimum = 0

For maximum; Let x = 0

[tex]240 = 12x + 8y[/tex]

[tex]240 = 12 * 0 + 8 * y[/tex]

[tex]240 = 8y[/tex]

Solve for y

[tex]x = 240/8[/tex]

[tex]x = 30[/tex]

See Attachment for graph

Ver imagen MrRoyal

The number of children that will be able to go to the zoo is 18.

"The missing question;

How many children will be able to go to the zoo if 8 adult tickets are purchased ?

The given parameters;

  • amount budgeted for the trip, = $240
  • cost of adult ticket, = $12
  • cost of children ticket, = $8

The equation representing the budget for the trip;

12x + 8y = 240

When 8 adult tickets are purchased, the possible number of children to be accommodated within the budget is calculated as follows;

12(8) + 8y = 240

96 + 8y = 240

8y = 240 - 96

8y = 144

[tex]y = \frac{144}{8} \\\\y = 18[/tex]

Thus, the number of children that will be able to go to the zoo is 18.

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