Answer:
[tex]y=2x-2[/tex] and image of (0,3) is (1,0).
Step-by-step explanation:
From the given graph it is clear that the line of Nolan Street passes through the points (0,-2) and (1,0).
So, the equation of Nolan Street is
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-(-2)=\dfrac{0-(-2)}{1-0}(x-0)[/tex]
[tex]y+2=2x[/tex]
[tex]y=2x-2[/tex]
So, the equation of the Nolan Street is [tex]y=2x-2[/tex].
It is given that the cartographer translates points on line m along the vector <1, −3> to draw Nolan Street. So, the rule of translation is
[tex](x,y)\to (x+1,y-3)[/tex]
The image of (0, 3) in this situation.
[tex](0,3)\to (0+1,3-3)=(1,0)[/tex]
The image of (0,3) is (1,0).