Question

Select the point that is a solution to the system of inequalities. Yx^2-4?

Answer 1

Answer:

C (1,2)

Step-by-step explanation:

The point that is a solution must satisfy both inequalities;

The inequalities are;

$y\:<\:x^2+3$

$y\:>\:x^2-4$

Point A

$(4,0)$

$0\:<\:16+3$: True

$0\:>\:16-4$:False

Point B (0,4)

$4\:<\:0+3$: False

$4\:>\:0-4$:True

Point C (1,2)

$2\:<\:1+3$: True

$2\:>\:1-4$:True

Point D(-2,-4)

$-4\:<\:4+3$: True

$-4\:>\:4-4$:False

The correct answer is C.