Answer:
[tex]x=-4\pm\sqrt5[/tex]
Step-by-step explanation:
So we have the equation:
[tex]x^2+8x+11=0[/tex]
First, subtract 11 from both sides:
[tex]x^2+8x=-11[/tex]
Now, add the c term. Divide 8 by 2 and then square it:
[tex](x^2+8x+16)=-11[/tex]
What we do to one side we must also do to the other. Thus:
[tex](x^2+8x+16)=-11+16[/tex]
Simplify:
[tex](x^2+8x+16)=5[/tex]
Perfect Square Trinomial:
[tex](x+4)^2=5[/tex]
Take the square root:
[tex]x+4=\pm\sqrt5[/tex]
Subtract 4:
[tex]x=-4\pm\sqrt5[/tex]
And that's our answer :)