Respuesta :

[tex]10c-f=-13+cd\ \ \ |add\ f\ to\ both\ sides\\\\10c=-13+cd+f\ \ \ \ |subtract\ cd\ from\ both\ sides\\\\10c-cd=f-13\\\\c(10-d)=f-13\ \ \ |divide\ both\ sides\ by\ (10-d)\\\\\boxed{c=\frac{f-13}{10-d} }[/tex]
ACCESS MORE
EDU ACCESS