Question

Shota is a dangerous fellow who likes to go rock climbing in active volcanoes. One time, when he was 303030 meters below the edge of a volcano, he heard some rumbling, so he decided to climb up out of there as quickly as he could. He climbed up at a constant rate. After 4.54.54, point, 5 seconds, he was 7.57.57, point, 5 meters below the edge of the volcano How fast did Shota climb? In total, how long did it take Shota to reach the edge of the volcano?

Answer 1

Answer:

Speed = 5m/s

Total time taken = 6 seconds

Step-by-step explanation:

Shota's initial position = 30 metres below the edge of a volcano

If Shota climbed at a constant rate:

Shota's position after 4.5 seconds = 7.5meters below the edge of the volcano

Shota's climbing speed :

Distance covered / time taken

Distance covered = (30 - 7.5) = 22.5 meters

Hence, speed = (22.5 / 4.5) = 5m/s

Time taken to reach edge of volcano:

Time left to reach edge = (distance left to cover / speed)

Time left to reach edge = (7.5 / 5) = 1.5 seconds

Total time taken: (4.5 + 1.5) = 6 seconds