A flagpole casts a shadow that is 40 feet long. at the same time, a man standing nearby who is 6 feet tall casts a shadow that is 50 inches long. how tall is the flagpole to the nearest foot?

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Answer:

The height of flagpole to the nearest foot is 58 feet.

Step-by-step explanation:

Given information:

Shadow of flagpole = 40 feet

Height of man = 6 feet

Shadow of man = 50 inches

We know that 1 feet = 12 inches

50 inches = [tex]\frac{50}{12}[/tex] feet

The actual height and shadow of man and flagpole are proportional.

Let the height of flagpole is h.

For flagpole,

[tex]\frac{height}{shadow}=\frac{h}{40}[/tex]

For man,

[tex]\frac{height}{shadow}=\frac{6}{\frac{50}{12}}\Rightarrow \frac{72}{50}=1.44[/tex]

Since the height and shadow of man and flagpole are proportional.

[tex]\frac{h}{40}=1.44[/tex]

Multiply both sides by 40.

[tex]h=1.44\times 40[/tex]

[tex]h=57.6\approx 58[/tex]

Therefore the height of flagpole to the nearest foot is 58 feet.

The height of the flagpole to the nearest feet is 58 feet

Similar triangle

Similar triangle are not necessarily the same sizes. There corresponding angles are congruent. The corresponding sides are ratio of each other.

The flag post triangle form a similar triangle with the man standing nearby.

Therefore, let's establish the following proportion to find the height of the flagpole.

50 inches = 4.16667 ft

  • x / 40 = 6 / 4.16667

cross multiply

4.16667x = 240

x = 240 / 4.16667

x = 57.59995392

x = 58 feet.

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