please solve each inequality and show you work thank you so much:)

2x – 7 > 3= ?

[tex]\frac{x}{4} +11\geq 8[/tex]= ?

[tex]-6x+7\geq 19[/tex]= ?


-10+4x>50= ?

[tex]\frac{x}{-2}[/tex]-17>-13= ?


[tex]8-2x\leq 46[/tex]= ?

[tex]-13x+1\leq -25[/tex]= ?

[tex]-7+\frac{x}{3} \ \textgreater \ -4[/tex]= ?

[tex]-9x-19\geq 17[/tex]= ?

[tex]16-x\ \textgreater \ 9[/tex]= ?

Respuesta :

Answer:

1) [tex]\boxed{x > 5}[/tex]

2) [tex]\boxed{x \geq -12}[/tex]

3) [tex]\boxed{x \leq -2}[/tex]

4) [tex]\boxed{x > 15}[/tex]

5) [tex]\boxed{x < -8}[/tex]

6) [tex]\boxed{x \geq -19}[/tex]

7) [tex]\boxed{x \geq 2}[/tex]

8) [tex]\boxed{x > 9}[/tex]

9) [tex]\boxed{ x \leq - 4}[/tex]

10) [tex]\boxed{x < 7}[/tex]

Step-by-step explanation:

1) [tex]2x-7 > 3[/tex]

Adding 7 to both sides

=> 2x > 3+7

=> 2x > 10

Dividing both sides by 2

=> x > 5

2) [tex]\frac{x}{4} + 11 \geq 8[/tex]

Subtracting 11 to both sides

[tex]\frac{x}{4} \geq 8 -11\\\frac{x}{4}\geq -3[/tex]

Multiplying both sides by 4

x ≥ -3 * 4

x ≥ -12

3) -6x+7 ≥ 19

Subtracting 19 to both sides

=> -6x ≥ 19-7

=> -6x ≥ 12

Dividing both sides by -6

=> x ≤ -2

4) -10 + 4x > 50

Adding 10 to b.s

=> 4x > 50+10

=> 4x > 60

Dividing b.s by 4

=> x > 15

5) [tex]\frac{x}{-2} - 17 > -13[/tex]

[tex]\frac{x}{-2} - 17 > -13\\Adding \ 17 \ to \ both \ sides\\\\\frac{x}{-2} > -13+17\\\\\frac{x}{-2} > 4\\Multiplying both sides by -2[/tex]

=> x < 4*-2

=> x < -8

6) 8 - 2x ≤ 46

Subtracting 8 from b.s

=> -2x ≤ 46-8

=> -2x ≤ 38

Dividing b.s by -2

=> x ≥ -19

7) -13x+1 ≤ -25

Subtracting 1 from both sides

=> -13x ≤ -25-1

=> -13x ≤ -26

Dividing both sides by -13

=> x ≥ 2

8) [tex]-7 + \frac{x}{3} > -4[/tex]

Adding 7 to b.s

=> x/3 > -4+7

=> x/3 > 3

Multiplying 3 to b.s

=> x > 3*3

=> x > 9

9) -9x-19 ≥ 17

Adding 19 to both sides

=> -9x ≥ 17+19

=> -9x ≥ 36

Dividing both sides by -9

=> x ≤ -4

10) 16 - x > 9

Adding x to both sides

=> 16 > 9 + x

Subtracting 9 from both sides

=> 16 - 9 > x

=> 7 > x

OR

=> x < 7

NOTE: Whenever, we divide the inequality by a negative signed term, the inequality changes to its opposite.

Answers:

[tex]\boxed{x > 5}\\ \boxed{x \geq -12}\\\boxed{x \leq -2}\\\boxed{x > 15}\\\boxed{x < -8}\\\boxed{x \geq -19}\\ \boxed{x \geq 2}\\\boxed{x > 9}\\\boxed{ x \leq -4}\\ \boxed{x < 7}[/tex]

Step-by-step explanation:

2x - 7 > 3

2x > 10

x > 5

x/4 + 11 ≥ 8

x/4 ≥ -3

x ≥ -12

-6x + 7 ≥ 19

-6x ≥ 12

x ≤ -2

-10 + 4x > 50

4x > 60

x > 15

-x/2 - 17 > -13

-x/2 > 4

-x > 8

x < -8

8 - 2x ≤ 46

-2x ≤ 38

x ≥ -19

-13x + 1 ≤ -25

-13x ≤ -26

x ≥ 2

-7 + x/3 > -4

x/3 > 3

x > 9

-9x -19 ≥ 17

-9x ≥ 36

x ≤ -4

16 - x > 9

-x > -7

x < 7

ACCESS MORE
EDU ACCESS