What volume of CO2 decomposes according to the following equation? CaCO3 is equal to CaO+CO2 {CaCO3 is equal to 100grams per mole, 1 mole of gas occupies 22.4dm cube at s.t.p}
Pls explain appropriately

Respuesta :

Answer:

as we know that CaO  +CO2 -------------- CaCO3

and it is given that CaCO3 = 100 grams/1 mole

so first we know that this equation is already balanced ,

according to stoichiometry , CaO = 22.4 litre,

because we know that if one mole of CaCO3 contains 22.4 litre ,

then one mole of CaO will also contain 22.4 litre [volume].

This can be only founded by the help of Stoichiometry.

Explanation:

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