Question

The temperature each hour in Elma, Texas on October 1 is modelled by the equation
t(h) = 10 cos(15h - 10)° + 30 where his hour of the day with 0 meaning midnight, and t is the
temperature in degrees Celsius. How hot did it get in Elma on October 1?

Answer 1

Answer:

$39.8^{\circ} C$

Step-by-step explanation:

We are given that the temperature each hour in Elma Texas on October 1 is modelled by the equation

$t(h)=10cos(15h-10)^{\circ}+30$

Where h=Hour of the day with 0 meaning midnight

t=Temperature in degree Celsius

We have to find the temperature on October 1.

Substitute h=0

$t(0)=10cos(15(0)-10)+30$

$t(0)=10cos(-10)+30$

$t(0)=39.8^{\circ} C$

Hence, the temperature in Elma on October 1=$39.8^{\circ} C$