Question

In the reaction of solid copper with silver nitrate, solid silver and copper (II) nitrate form. How many grams of solid silver will form if 24.58 g of solid copper are used?

Answer 1

Answer:

83.4g

Explanation:

The reaction expression is given as:

       Cu   + 2AgNO₃  →   Cu(NO₃)₂  +  2Ag

Mass of copper  = 24.58g

Unknown:

Mass of silver produced  = ?

Solution:

To solve this problem, let us find the number of moles of the copper;

   Number of moles = $\frac{mass}{molar mass}$  

 Molar mass of Cu  = 63.6g/mol

   Number of moles  = $\frac{24.58}{63.6}$   = 0.39mole

    1 mole of Cu will produce 2 moles of Ag

   0.39 mole of Cu will produce 0.39 x 2 = 0.77moles of Ag

Mass of Ag  = number of moles x molar mass = 0.77 x 107.9  = 83.4g