Number 19 sorry for all these
![Number 19 sorry for all these class=](https://us-static.z-dn.net/files/d24/18b21d8fb2cb14881c479ecf7eabb177.png)
Answer:
Option A is the correct option
Step-by-step explanation:
[tex] \frac{2 {x}^{2} - 10x - 28}{6x} \times \frac{6}{x - 7} [/tex]
Factor out 2 from the expression
[tex] \frac{2( {x}^{2} - 5x - 14)}{6x} \times \frac{6}{ x - 7} [/tex]
Weite -5x as a difference
[tex] \frac{2( {x}^{2} + 2x - 7x - 14)}{x} \times \frac{1}{ x - 7} [/tex]
Factor out
[tex] \frac{2(x(x + 2) - 7(x + 2))}{x} \times \frac{1}{x - 7} [/tex]
Factor X+2 from the expression
[tex] \frac{2(x + 2)(x - 7)}{x} \times \frac{1}{x - 7} [/tex]
Reduce the expression with x-7
[tex] \frac{2(x + 2)}{x} [/tex]
Distribute 2 through the parentheses
[tex] \frac{2x + 4}{x} [/tex]
Hope this helps...