Answer:
909.8 millibars.
Step-by-step explanation:
The mean sustained velocity, v be determined by the equation:
[tex]v=6.3\sqrt{1013-p}[/tex], where p is the air pressure, in millibars, at the center of the hurricane.
Given that: v=64 meters per second, we are to find the value of p.
[tex]64=6.3\sqrt{1013-p}\\$Square both sides to eliminate the square root sign\\(64)^2=(6.3\sqrt{1013-p})^2\\4096=39.69(1013-p)\\$Divide both sides by 39.69$\\\dfrac{4096}{39.69}=1013-p\\ $Therefore:$\\p=1013-\dfrac{4096}{39.69}\\\\p=909.8$ millibars[/tex]
The approximate air pressure at the center of a hurricane when the mean sustained wind velocity is 64 meters per second is 909.8 millibars.
