Question

Find the x- and y- intercept of the line. x + 4y =36

Answer 1

Plug in 0 for x to find the y-intercept
0 + 4y = 36
4y = 36
y = 9
y-intercept (0, 9)

Plug in 0 for y to find the x-intercept
x + 4(0) = 36
x = 36
x-intercept (36, 0)

Answer 2

The intersections be x-intercept(s): (36,0) and  

y-intercept(s): (0,9)

How to estimate x- and y- intercept of the line?

Let, $x + 4y = 36$

To find the x-intercept(s), substitute in 0 for y and solve for x.

$x + 4(0) = 36$

Simplify x + 4(0).

Multiply 4 by 0.

x + 0 = 36

Add x and 0.

$x = 36$

x-intercept(s) in point form.

x-intercept(s): (36,0)

To find the y-intercept(s), substitute in 0 for x and solve for y.

$(0)+4 y=36$

Solving the above equation, we get

Add 0 and 4y.

$4y = 36$

Divide each term by 4 and simplify.

Divide each term in 4y = 36 by 4.

$\frac{4 y}{4}=\frac{36}{4}$

Cancel the common factor of 4.

Cancel the common factor.

$\frac{4 y}{4}=\frac{36}{4}$

Divide y by 1.

$y=\frac{36}{4}$

Divide 36 by 4.

$y = 9$

y-intercept(s) in point form.

y-intercept(s): (0,9)

Therefore, the intersections be x-intercept(s): (36,0) and  

y-intercept(s): (0,9).

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