Answer:
a) Mean number of beans = 33.4 per coco pad
b) Standard deviation of the beans = 5.2 per coco pad
Step-by-step explanation:
Step(i):-
a)
Given data 30, 28, 30, 35, 40, 25, 32, 36, 38 and 40.
mean of beans
x⁻ = ∑x/n
[tex]x^{-} = \frac{30+ 28+30+35+40+25+32+36+38 + 40.}{10} = 33.4[/tex]
Mean number of beans per coco pad = 33.4
step(ii):-
b)
standard deviation
∑(xi - x⁻)² = (30-33.4)²+ (28-33.4)²+(30-33.4)²+(35-33.4)²+(40-33.4)²+(25-33.4)²+(32-33.4)²+(36-33.4)²+ (38-33.4)²+(40-33.4)²
On calculation , we get
∑(xi - x⁻)² = 242.4
standard deviation
= [tex]\sqrt{\frac{sum((x-x^{-} )^{2} }{n-1} } = \sqrt{\frac{242.4}{10-1} } = 5.189[/tex]
Standard deviation of the beans (σ) = 5.2 per coco pad