HELPPPPPPPPPP!!!!!!! Calculate the correlation coefficient for the following data, showing all work. What does it tell you about the data?
![HELPPPPPPPPPP Calculate the correlation coefficient for the following data showing all work What does it tell you about the data class=](https://us-static.z-dn.net/files/d67/bb46c5ab60e347822ff786fdc3e5f78c.png)
Answer:
I will show the way.
Step-by-step explanation:
r is the correlation coefficient
[tex]r=\frac{SSxy}{\sqrt{(SSxx)(SSyy)}}[/tex]
To find SSxy
SSxy= ∑[tex]xy[/tex]- ∑[tex]\frac{(x)(y)}{n}[/tex]
To find SSxx
SSxy= ∑[tex]x^{2}[/tex]- [tex]([/tex]∑x[tex])^{2}[/tex]/n
To find SSyy
SSxy= ∑[tex]y^{2}[/tex]- [tex]([/tex]∑y[tex])^{2}[/tex]/n
if your r is near +1, it shows strong positive correlation. Y is proportional to X.
And if it nears -1, it would show strong negative correlation. Y is inversely proportional to X.
The correlation coefficient for the following data is 7,321.95.
Here are the steps to take in calculating the correlation coefficient:
The value of x are 43, 21, 25, 42, 57, 59
The value of y are 99, 65, 79, 75, 87, 81
The mean of x is 41.166
The mean of y is 81.
Standard deviation of x:
σ =√∈([tex]x_{i}[/tex] - ч)[tex]^{2}[/tex] / N
σ = √(247 - 41.166)² / 6
σ = √7,061.47
= 84.03
The standard deviation of y:
σ =√∈([tex]x_{i}[/tex] - ч)² / N
σ = √(486-81)² / 6
σ = √1,64,025 / 6
σ = √27,337.5
σ = 522.81
Multiply both x and y standard deviations
84.03 * 522.81 = 43,931.7243
Divide the sum
43,931.72 / 6 = 7,321.95
A correlation coefficient is a number between -1 and 1 that tells you the strength and direction of a relationship between variables.
Learn more about correlation coefficient here: brainly.com/question/4219149
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