Question

the line of symmetry for the quadratic equation y=ax^2+8x-3 is x=4. What is the value of “a”?

Answer 1

Answer:

The value of a is -1.

Step-by-step explanation:

The line of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves.

For a quadratic function in standard form, $y=ax^2+bx+c$, the line of symmetry is a vertical line given by $x=-\frac{b}{2a}$.

We know that the quadratic equation, $y=ax^2+8x-3$, has x = 4 as line of symmetry. Therefore, the value of a is:

                                                         $4=-\frac{8}{2a}\\\\4=-\frac{4}{a}\\\\4a=-4\\\\a=-1$

Answer 2

Answer:

a=-1

Step-by-step explanation:

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