Answer:
the mass of water heated is m water = 18.81 g
Explanation:
Assuming a specific heat of iron of C iron =0.450 J/g°C (from tables) , then if we neglect heat losses to the environment , all the heat absorbed by the water is the one released by the iron ball.
Therefore
heat released= Q = m iron * C iron * (T initial iron - T final ) = 5 g * 0.450 J/g°C ( 200°C - 25°C) = 393.75 J
where
m= mass , T= temperature
then
heat released= heat absorbed =Q = m water * C water * (T final - T initial water)
m water = Q/ [C water * (T final - T initial water)] = 393.75 J/[ 4.186 J/g°C *( 25°C-20°C)] = 18.81 g
m water = 18.81 g
