Answer:
The overview of the problem is listed in the segment below on the explanation.
Step-by-step explanation:
The given values are:
Sample mean, [tex]\bar{Z}=0.017[/tex]
The hypothesized mean value, [tex]\mu_{0}=0.02[/tex]
Population standard deviation, [tex]\sigma=0.036[/tex]
As we know, the status of the test is as follows:
⇒ [tex]z^* = \frac{\bar X - \mu_0}{\frac{\sigma}{\sqrt{n}}}[/tex]
On putting the values, we get
⇒ [tex]= \frac{0.017 - 0.02}{\frac{0.036}{\sqrt{40}}}[/tex]
⇒ [tex]=-0.5357[/tex]
Now, even though this is a one-sided check, here so the p-value is measured as:
[tex]p=P(Z<-0.5357)[/tex]
[tex]=0.2[/tex]
Consequently p-value > 0.05 the check isn't relevant so there is no data to suggest that perhaps the concentration of mercury fallen from 1980 until 2012.