Answer:
Explanation:
The hydroxyl ion concentration of the solution [OH⁻] is 5.5 x 10⁻¹⁰M
Problem:
To find [H₃O⁺] and the pH of the solution:
We know that the ionic product of water has been experimentally determined and it is given for a pure water as 1.0 x 10⁻¹⁴mol²dm⁻⁶ at 25°C.
So : [H₃O⁺][OH⁻]= 10⁻¹⁴mol²dm⁻⁶ at 25°C
To find the concentration of the hydroxonium ions:
[H₃O⁺] = [10⁻¹⁴] / [OH⁻]
[H₃O⁺] = 10⁻¹⁴ / 5.5 x 10⁻¹⁰ = 1.8 x 10⁻⁵M
To find the pH of the solution, we know that ;
pH = -log[H₃O⁺] = -log 1.8 x 10⁻⁵ = 4.74
The solution is acidic
