Respuesta :
Answer:
3) 112
Step-by-step explanation:
Given:
Sugar used = 1¾ pounds
Butter used = [tex] \frac{7}{8}[/tex]
Let sugar and butter be denoted as A and B.
This means the ratio of sugar to butter is A:B
Also, A+B = 168 Pounds
Let's first simplify 1¾ by multiplying 4 by 1,then add 3. We now have amount of sugar as [tex] \frac{7}{4}[/tex].
Therefore,
[tex] A:B = \frac{7}{4} : \frac{7}{8}[/tex]
Dividing them, we have:
[tex] \frac{A}{B} = \frac{\frac{7}{4}}{\frac{7}{8}} [/tex]
[tex] \frac{A}{B} = \frac{7}{4} * \frac{8}{7} [/tex]
Solving further, we have:
[tex] \frac{A}{B} = 2 [/tex]
[tex] A= 2B [/tex]
We already know A+B = 168
Let's substitute 2B for A
We have:
2B + B = 168
3B = 168
B = 56
To find A, lets substitute 56 for B,
We have:
A + B = 168
A + 56 = 168
A = 168 - 56
A = 112
Therefore, the baker uses 112 pounds of sugar
Answer:
The baker uses 112 pounds of sugar
Step-by-step explanation:
The baker mixes 1 3/4 pounds of sugar for every 7/8 pounds of butter to begin frosting. The baker uses 168 pounds of butter and sugar to start the frosting .
1 3/4 = 7/4 pounds of sugar for every 7/8 pounds of butter. It can be express in ratio as
7/4 of sugar : 7/8 of butter
The amount of sugar the baker uses can be solved using the proportion below,
amount of sugar = a
amount of butter plus sugar = 168
Therefore,
7/4 + 7/8 = (14 + 7)/8 = 21/8(total used)
7/4 ÷ 21/8 = a/168
7/4 × 8/21 = a/168
8/12 = a/168
cross multiply
12a = 1344
a = 1344/12
a = 112 pounds
The baker uses 112 pounds of sugar