Question

A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of the height of the big locker what is the total volume of one big locker and one small locker

Answer 1

Answer:

$0.54\,\,m^3$

Step-by-step explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

Dimensions of a small locker are 0.5 m × 0.6 m × $\frac{1.2}{2}=0.6\,\,m$ (as height of small locker is half the height of big locker )

To find: total volume of one big locker and one small locker

Solution:

Volume of cuboid = length × breadth × height

Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

= $0.5\times 0.6\times 1.2+0.5\times 0.6\times 0.6$

$=0.5\times 0.6\left ( 1.2+0.6 \right )\\=0.3(1.8)\\=0.54\,\,m^3$

Answer 2

Answer:

Volume of big locker = 0.36 $m^{3}$

Volume of small locker = 0.18 $m^{3}$

Total volume = 0.54 $m^{3}$

Step-by-step explanation:

We are given the following:

Width of larger locker = 0.5 m

Depth of larger locker = 0.6 m

Height of larger locker = 1.2 m

It is a cuboid like structure and it is well known that Volume of a cuboid structure = $\text{width} \times \text{depth} \times \text{height}$

So, volume of larger locker =

$0.5 \times 0.6 \times 1.2\\\Rightarrow .36m^{3}$

Width of smaller locker = 0.5 m

Depth of smaller locker = 0.6 m

Height of smaller locker = $\dfrac{1.2}{2} = 0.6m$

Volume of a cuboid structure = $\text{width} \times \text{depth} \times \text{height}$

So, volume of smaller locker =

$0.5 \times 0.6 \times 0.6\\\Rightarrow 0.18m^{3}$

Adding both the volumes, Total volume = 0.54 $m^{3}$