Question

Cyrus solved a quadratic equation. His work is shown below.
In which step did Cyrus make an error?
\begin{aligned} \dfrac{1}{3}(x-1)^2&=12 \\\\ (x-1)^2&=36&\text{Step }1 \\\\ x-1&=6&\text{Step }2 \\\\ x&=7&\text{Step }3 \end{aligned}
3
1
​
(x−1)
2

(x−1)
2

x−1
x
​

=12
=36
=6
=7
​

Step 1
Step 2
Step 3
​

Answer 1

Answer:

Step 2

Step-by-step explanation:

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