Question

38. Consider the following equilibrium:
2CO(g) + O2(g) =2CO2
Keg=4.0 x 10-10
What is the value of Key for 2CO2(g) + 2COR + O2g) ?​

Answer 1

Answer:

$Key=2.5x10^{-9}$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the equilibrium constant value for the reverse reaction:

$2CO_2(g) \rightleftharpoons 2CO(g) + O_2(g)$

By knowing that the equilibrium expression is actually:

$Key =\frac{[CO]^2[O_2]}{[CO_2]^2} =\frac{1}{Keg}$

Thus, we plug in and solve for the inverse of Keq to obtain Key as follows:

$Key =\frac{1}{4.0x10^{-10}}\\\\Key=2.5x10^{-9}$

Regards!