Question

When the phenol shown below is treated with KOH, it forms a product whose IR spectrum does not show an absorption in the 3200-3600 cm-1 region. Propose a structure for the product.?

Answer 1

Answer:

Explanation:

The first attached diagram shows the proposed phenol that is being treated with KOH to form Oxonine (CₐHₐO).

Reaction of Arylhalide after treatment with KOH lead to the displacement of Bromine atom with the hydrogen from the hydroxyl (OH) substituent , then  forming HBr  , leaving the oxy (-O) atom  alone to form an Oxonine compound.

Therefore the propose structure for the product (Oxonine) CₐHₐO is shown in the second diagram attached below.