Answer:
C = 0.7385J/g°C
Explanation:
Heat energy (Q) = 54J
Mass (m) = 2.47g
Initial temperature (T1) = 17.10°C
Final temperature (T2) = 46.70°C
Specific heat capacity of substance (c) = ?
Heat energy of a substance (Q) = Mc∇T
Q = heat energy
M = mass of the substance
C = specific heat capacity of the substance
∇T = change in temperature of substance = T2 - T1
Q = mc∇T
Q = mc (T2 - T1)
54 = 2.47 * c * (46.70 - 17.10)
54 = 2.47 * 29.6 * c
54 = 73.112c
C = 54 / 73.112
C = 0.7385
Specific heat capacity of the substance is 0.7385J/g°C
B.
The specific heat capacity of the above substance does not match any metal in the periodic table, however the closest to it was potassium with a value of 0.7536J/g°C and silicone with value of 0.711756J/g°C
Answer:
The specific heat of the substance is 0.739 J/g°C
The substance can be glass or SiO2
Explanation:
Step 1: Data given
Heat required = 54 J
Mass of the substance = 2.47 grams
Initial temperature = 17.10 °C
Final temperature = 46.70 °C
Step 2: Calculate the specific heat of the substance
Q = m*c¨*ΔT
⇒with Q = the heat required =54 J
⇒with m = the mass of the substance = 2.47 grams
⇒with c = the specific heat of the substance = TO BE DETERMINED
⇒with ΔT = the change of temperature = T2 - T1 = 46.70 - 17.10 = 29.60 °C
c = Q / (m*ΔT)
c = 54 / (2.47 * 29.60)
c = 0.739 J/g°C
The specific heat of the substance is 0.739 J/g°C
The substance can be glass or SiO2
