Answer:
The rate at which the horizontal velocity of the ball changes every second is, 19%.
Step-by-step explanation:
The exponential decay function is given by:
[tex]y=a(1-r)^{t}[/tex]
Here,
y = final value
a = initial value
r = decay rate
t = time
The relationship between the elapsed time, t, in seconds, since Mustafa threw the ball, and its horizontal velocity, V (t) is:
[tex]V(t)=4\cdot (0.81)^{t}[/tex]
The expression for the horizontal velocity of the ball represents the exponential decay function.
On comparing the two equations we get:
[tex]1-r=0.81\\r=1-0.81\\r=0.19[/tex]
Thus, the rate at which the horizontal velocity of the ball changes every second is, 19%.