Question

On a coordinate plane, a line goes through points (negative 2, 1) and (0, negative 3). Y = negative StartFraction 2 Over 9 EndFraction x + 2. Two separate linear functions are expressed by the graph and by the equation. Select all that apply. The slope is negative for both functions. The equation has a steeper slope than the line in the graph. The slope of the line in the graph is -2. The graph and the equation express an equivalent function.

Answer 1

Answer:Two separate linear functions are expressed by the graph and by the equation. Select all that apply.

VThe slope is negative for both functions.

XThe equation has a steeper slope than the line in the graph.

VThe slope of the line in the graph is -2.

XThe graph and the equation express an equivalent function.

Step-by-step explanation: 1 and 3 got it right on e2020 please mark brainliest

Answer 2

Both lines have a negative slope and The slope of the line in the graph is -2

The equation of a straight line is given by:

y = mx + b;

where m is the slope of the line, b is the y intercept, y,x are variables.

Given that a line goes through (-2, 1) and (0, -3), the equation of this line is given by:

$y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-1=\frac{-3-1}{0-(-2)} (x-(-2))\\\\y-1=-2(x+2)\\\\y-1=-2x-4\\\\y=-2x-3$

Therefore the slope of the line in the graph is -2

The second line is given by:

$y=-\frac{2}{9} x+2$

This line has a slope of -2/9

a) Both lines have a negative slope

b) The graph has a steeper slope

c) The slope of the line in the graph is -2

d) The graph and equation do not express an equivalent function because they have different equations

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