Question

What is the center of the circle with the following equation (x+1)²+ (y-3)²= 64? *
(1,3)
(3,1)
(-1,3)
(1,-3)

Answer 1

Answer:

The center of the circle is (-1,3).

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$ where center is known as $(h,k)$ and the radius known as $r$.

-The following equation:

$(x+1)^2+(y-3)^2=r^2$

-So, according to the following equation, the center would be (-1,3), because the center is $(h,k)$, based on the equation of a circle:

$(h,k) = (-1,3)$