Answer:
A
Step-by-step explanation:
Factor the numerators/ denominators where possible, that is
[tex]\frac{-(x-5)}{(x+4)(x-1)}[/tex] ÷ [tex]\frac{(x-5)(x+3)}{(x+4)(x+1)}[/tex]
Leave the first fraction, change division to multiplication and turn the second fraction upside down.
= [tex]\frac{-(x-5)}{(x+4)(x-1)}[/tex] × [tex]\frac{(x+4)(x+1)}{(x-5)(x+3)}[/tex]
Cancel the factors (x - 5) and (x + 4) from numerator/denominator
= [tex]\frac{-1}{(x-1)}[/tex] × [tex]\frac{(x+1)}{(x+3)}[/tex]
= [tex]\frac{-(x+1)}{(x-1)(x+3)}[/tex] , x ≠ 1, x ≠ - 3
