What two numbers have a sum of 191 and a difference of 63? *Hint: Create a system where one equation represents the sum and one equation represents the difference. ​(smaller number) ​ (bigger number)

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Answer:

127 &64

Step-by-step explanation:

x+y=191 eq(1) & x-y=63 eq(2)

x=63+y then put in the eq(1)

63+y+y=191

2y=191-63

y=64 then put in the eq(2)

x-y=63

x= 63+y

x=63+64

x=127

Answer:

both numbers are 127 and 64

Step-by-step explanation:

x= one of the numbers

191-x= the other number

(191-x)-x=63

191-x-x=63 (combine like terms)

191-2x=63 (rearrange)

191-63-2x (simplify)

128=2x

64=x

(127 +64=191)

(127-64= 63)