Question

$(1 x^{2000})(1 x)^{1998}=(2x)^{1999}$

Answer 1

Hello,
$x^{2000}*x^{1998}=2^{1999}*x^{1999}\\ ==\textgreater\ x^{2000+1998}=2^{1999}*x^{1999}\\ ==\textgreater\ x^{2000+1998-1999}=2^{1999}\\ ==\textgreater\ x^{1999}=2^{1999}\\ ==\textgreater\ x=2$