George's page contains twice as many type words as Bill's paid and Bill's page contains 50 fewer words and Charlie's page. If each person can type 60 words per minute,after one minute, the difference between twice the number of words on bills page and the number of words on Charlie's paid 210. How many words did bills page contain initially?

Let g be the number of words on George's page. We know that George's page contains twice as many as Bill's; letting b represent Bill's page, this gives us

g = 2b

Bill's page contains 50 fewer words than Charlie's page; letting c represent Charlie's page, this gives us

b = c-50

Each person can type 60 words per minute. After 1 minute, Bill's page would be represented by b-60 and Charlie's would be c-60.

The difference between twice the number of words on Bill's page, 2(b-60), and Charlie's page, c-60, is 210:

2(b-60)-(c-60) = 210

Substituting c-50 for b,

2((c-50)-60)-(c-60) = 210

2(c-50-60)-(c-60) = 210

2(c-110)-(c-60) = 210

2c-220-c--60 = 210

2c-220-c+60 = 210

Combining like terms,

c-160 = 210

Add 160 to each side,

c-160+160=210+160

c = 370

Charlie's page had 370 words on it; this means Bill's had 50 fewer, or 370-50 = 320.