Answer:
Step-by-step explanation:
I used the paired sample t test as the same population of 40 cars is being tested.
The Hypothesis:
H0: = 0
Ha: 0
The Test statistic:
The p value (2 tail) at t = 2.65, df = n - 1 = 40 - 1 = 39 is 0.0116
The Critical value at = 0.01, df = 39 is 2.7079
The Decision Rule: If t observed > 2.7079, Reject H0.
Also if p value is < (0.01), Then Reject H0.
The Decision: Since t observed < 2.7079, Fail to reject H0.
Also Since p value (0.0116) > 0.01, We Fail to Reject H0.
The Conclusion: Fail To Reject H0. There is insufficient evidence at the 99% significance level to conclude that there is a significant difference in the mean number of gallons used between the 2 types of gasoline.