Answer:
Explanation:
Here we have the mass of CO₂ added = 340 g
From
[tex]Number \, of \, moles = \frac{Mass}{Molar \, mass}[/tex]
We have, where the molar mass of CO₂ is 44.01 g/mol
Therefore,
[tex]Number \, of \, moles = \frac{340}{44.01} = 7.73 \, \, \, moles[/tex]
71. Included drawing attached
72. Here we have the pressure of the gas given by Charles law which can be resented as follows;
[tex]\frac{P_1}{P_2} =\frac{T_1}{T_2}[/tex]
Where:
P₁ = Initial pressure = 6.1 atmospheres
P₂ = Final pressure
T₁ = Initial Temperature = 293 K
T₂ = Initial Temperature = 313 K
Therefore,
[tex]P_2= T_2 \times \frac{P_1}{T_1} = 313 \times \frac{6.1}{293} = 3.312 \, \, \, atmospheres[/tex]