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A manufacturer makes conical funnels for professional painters. The
funnels are formed from plastic with an 8-inch diameter base and height
of 9 inches. After the cones cool, a machine cuts off 1 inch of the tip to
leave a 1-inch diameter hole in the end. What is the volume of the funnel?
Round your answer to the nearest tenth and do NOT include units.

Respuesta :

Answer: 151

Step-by-step explanation:

In this situation we have two cones, the big cone with volume [tex]V_{big}[/tex] and the small cone with volume [tex]V_{small}[/tex].

Now, if we want to know the total volume [tex]V_{T}[/tex] we have to substract [tex]V_{small}[/tex] from  [tex]V_{big}[/tex], but first we have to calculate each volume:  

For the big cone:

[tex]V_{big}=\frac{\pi R^{2} H}{3}[/tex]

Where:

[tex]R=\frac{Diameter}{2}=\frac{8 in}{2}=4 in[/tex]

[tex]H=9 in[/tex]

Then:

[tex]V_{big}=\frac{\pi (4 in)^{2} 9 in}{3}[/tex]

[tex]V_{big}=150.79 in^{3}[/tex] Volume of big cone

For the small cone:

[tex]V_{small}=\frac{\pi r^{2} h}{3}[/tex]

Where:

[tex]r=\frac{diameter}{2}=\frac{1 in}{2}=0.5 in[/tex]

[tex]h=1 in[/tex]

Then:

[tex]V_{small}=\frac{\pi (0.5 in)^{2} 1 in}{3}[/tex]

[tex]V_{small}=0.261 in^{3}[/tex] Volume of small cone

Calculating the total volume:

[tex]V_{T}=V_{big}-V_{small}[/tex]

[tex]V_{T}=150.79 in^{3}-0.261 in^{3}[/tex]

Finally:

[tex]V_{T}=150.52 in^{3} \approx 151 in^{3}[/tex]

Answer:

151 in^3

Step-by-step explanation:

Find the volume of the cones the subtract them to get your final answer

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