Respuesta :
Answer: 151
Step-by-step explanation:
In this situation we have two cones, the big cone with volume [tex]V_{big}[/tex] and the small cone with volume [tex]V_{small}[/tex].
Now, if we want to know the total volume [tex]V_{T}[/tex] we have to substract [tex]V_{small}[/tex] from [tex]V_{big}[/tex], but first we have to calculate each volume:
For the big cone:
[tex]V_{big}=\frac{\pi R^{2} H}{3}[/tex]
Where:
[tex]R=\frac{Diameter}{2}=\frac{8 in}{2}=4 in[/tex]
[tex]H=9 in[/tex]
Then:
[tex]V_{big}=\frac{\pi (4 in)^{2} 9 in}{3}[/tex]
[tex]V_{big}=150.79 in^{3}[/tex] Volume of big cone
For the small cone:
[tex]V_{small}=\frac{\pi r^{2} h}{3}[/tex]
Where:
[tex]r=\frac{diameter}{2}=\frac{1 in}{2}=0.5 in[/tex]
[tex]h=1 in[/tex]
Then:
[tex]V_{small}=\frac{\pi (0.5 in)^{2} 1 in}{3}[/tex]
[tex]V_{small}=0.261 in^{3}[/tex] Volume of small cone
Calculating the total volume:
[tex]V_{T}=V_{big}-V_{small}[/tex]
[tex]V_{T}=150.79 in^{3}-0.261 in^{3}[/tex]
Finally:
[tex]V_{T}=150.52 in^{3} \approx 151 in^{3}[/tex]
Answer:
151 in^3
Step-by-step explanation:
Find the volume of the cones the subtract them to get your final answer