Question

Which expression defines the given series for seven terms? –3 + (–1) + 1 + . . .

a.Σ (2n-5)
b.Σ (2-5n) c.Σ (5n-2) d.Σ (5-2n)

Answer 1

$-3+(-1)+1+...\\\\a_1=-3;\ a_2=-1;\ a_3=1\\\\It's\ an\ arithmetic\ sequence\ where\ the\ common\ difference\\is\ equal\ d=a_2-a_1=-1-(-3)=-1+3=2.\\\\a_n=a_1+(n-1)d\\\\a_n=-3+(n-1)\cdot2=-3+2n-2=2n-5\\\\Answer:\boxed{\sum\limits_{n=1}^7(2n-5)}\to\fbox{a.}$

Answer 2

Answer: $\sum^{7}_{n=1}(2n-5)$

Step-by-step explanation:

Given: The first term of the series $a= -3$

The second term of the series $a_2= -1$

The third term of the series $a_3= 1$

The common difference=$d=a_3-_a_2=a_2-a_1=2$

Now, the nth term of this series will be given by :-

$a_n=a+d(n-1)\\\\\Rightarrow\ a_n=-3+2(n-1)\\\\\Rightarrow\ a_n=-3+2n-2\\\\\Rightarrow\ a_n=2n-5$

Hence, the expression defines the given series for seven terms will be

$\sum^{7}_{n=1}(2n-5)$