The number y of raccoons in an area after x years can be modeled by the function y= 0.4x^2+2x+2. When were there about 50 raccoons in the area . Round your answer to the nearest year

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Answer:

9 years.

Step-by-step explanation:

For 50 raccoons the equation is

0.4x^2+2x+2 = 50

0.4x^2+2x - 48 = 0

x =  [-2 +/- sqrt(2^2- 4* 0.4*(-48)] / (2*0.4)

= (-2 +/- sqrt 9) / 0.8

=  8.74 , - 13.75   (ignore the negative).

So it's 9 years.

A function assigns the values. The time when there were 50 racoons in the area is 8.736 years.

What is a Function?

A function assigns the value of each element of one set to the other specific element of another set.

Given that the number y of raccoons in an area after x years can be modelled by the function y= 0.4x²+2x+2. Therefore, there were 50 racoons in the area at time,

50 = 0.4x² + 2x + 2

0.4x² + 2x - 48 = 0

[tex]x = \dfrac{-2 \pm \sqrt{2^2 - 4(0.4)(-48)}}{2(0.4)}\\\\x = \dfrac{-2 \pm \sqrt{4 + 76.8}}{0.8}\\\\x = \dfrac{-2 \pm 8.9888}{0.8}\\\\x = 8.736, -13.736[/tex]

Since the time can not be negative, Hence, the time when there were 50 racoons in the area is 8.736 years.

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