Question

Find the solution set
x^2 +5x-14=0

Answer 1

Step-by-step explanation:

1. Make 2 parenthesis, extract x and put it in both parenthesis. The first parenthesis will have the sign of the number in the middle +5x, the second parenthesis will have the product of the multiplication of the sign of the second and third number; (+)(-) = -. Then, find 2 numbers that multiplied by each other give the third number as a result and added up or substracted give the result of the number in the middle. Here, 7 times 2 is 14 and +7 -2 = +5

$x^2+5x-14=0$

$(x+7)(x-2)=0$

Equal both results to zero.

$x+7=0\\x=-7$

$x-2=0\\x=2$