Answer:
Option C
Explanation:
As per the lens equation -
[tex]\frac{1}{f} = \frac{1}{v} + \frac{1}{u}[/tex]
where f is the length of focus of the lens
and V is the distance of the image
and U is the distance of the object
In case of lenses covered with tape, will have no impact on the distance of the image and the object as focal length is property of glass of lens.
And also
[tex]M = \frac{h_i}{h_o}[/tex][tex]\frac{h_i}{h_o} = \frac{-v}{u}[/tex]
Since there is no change in the distance of the image and the object due to tape on lens, the image and object height will remain same.
Thus, option C is correct