Respuesta :
Answer:
it should be 75%
Explanation:
because they have both the (B) and (b) allele
when you divide them into a into the chart they should have the possiblity of one child with (BB) , two with (Bb) and one with (bb) * i added a chart to help reference what i'm talking
![Ver imagen popejoh000](https://us-static.z-dn.net/files/d3d/68833c06d4280d65c486a15a1aa3c686.jpg)