Question

A business owner noted the features of the 100 100100 cars parked at the business. Here are the results: Sunroof2 doors4 doors 25 25 14 14 13 13 0 0 20 20 18 18 0 0 10 10 In this sample, are the events " 2 22 doors" and " 4 44 doors" mutually exclusive? Choose 1 answer: Choose 1 answer: (Choice A) A Yes (Choice B) B No Find the probability that a randomly selected car from this sample had 2 22 doors or 4 44 doors. P ( 2 doors OR 4 doors ) = P(2 doors OR 4 doors)=P, left parenthesis, start text, 2, space, d, o, o, r, s, space, O, R, space, 4, space, d, o, o, r, s, end text, right parenthesis, equals

Answer 1

Question:

In this sample, are the events "222 doors" and "444 doors" mutually exclusive?

Answer to question above: Yes

Answer to big question:

P( 2 doors OR 4 doors) = 0.77

Step-by-step explanation:

14 + 18 + 20 + 25 + 0 + 0 = 77 of the 100 cars that had two doors or four doors.

Answer 2

The probability that a randomly selected car from this sample had 222 doors or 444 doors is

P=0.77

What is the probability that a randomly selected car from this sample had 222 doors or 444 doors?

Question Parameter(s):

Sunroof2 doors4 doors 25 25 14 14 13 13 0 0 20 20 18 18 0 0 10 10

Generally, the equation for the Probability  is mathematically given as

P=(2doors or 4doors)

Therefore

P=(14 + 18 + 20 + 25 + 0 + 0 )/100

P=0.77

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