Question

The second side of a triangular deck is 4 feet longer than the shortest​ side, and the third side is 4 feet shorter than twice the length of the shortest side. if the perimeter of the deck is 56 ​feet, what are the lengths of the three​ sides?

Answer 1

Let's assume

first side as shortest side

and shortest side =x

we are given

the second side of a triangular deck is 4 feet longer than the shortest​ side

so, second side is

$=x+4$

the third side is 4 feet shorter than twice the length of the shortest side

so, third side is

$=2x-4$

now, we are given

perimeter =56

so,

first side + second side + third side =56

we get

$x+x+4+2x-4=56$

$x+x+2x=56$

now, we can solve for x

$4x=56$

$x=14$

so,

first side is 14 feet

Second side is:

$=14+4$

$=18 feet$

Third side is:

$=2*14-4$

$=24feet$